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zalisa [80]
3 years ago
5

Name the expression

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

since 7 is raised to the power 0 the answer is

a) linear polynomial with zero terms

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The first term of an arithmetic sequence is a1 = 2, and the third term is a3 = 6. Which of the following could be formula(s) for
Ulleksa [173]

Answer:

A

Step-by-step explanation:

an=2(1)=2

an=2(3)=6

8 0
3 years ago
kins age is twice that of her sister when you add kims age to her sisters you get 24 how old is each sister (a)write a equation
zimovet [89]

Kim's age is twice of that of her sister. We'll let k2 = Kim and k = Kim's sister.

So, k2. When you add Kim's age to her sister age you get 36.

Because Kim is twice the age of her sister k2. And because it said 'add' then we put a + sign. k2 + s = 36. Now let's solve it. 

k2 + k = 36 < Given

3k = 36 < Combine like terms

k = 12 < Divide both sides by 3

We know Kim's sister is 12 y/o but what about Kim herself? Earlier we assigned Kim to k2. Substitute 12 for k and you get 12(2) = 24

Kim's sister is 12 y/o and Kim is 24 y/o

Please give Brainliest!

8 0
3 years ago
Read 2 more answers
3 5/6 : 9 5/6 =<br><br> Divide using reciprocals
sashaice [31]
Yan po sana makatulpng

8 0
2 years ago
Triangle ABC hac three sides with these lengths: AB=9, BC=40, and CA=41. What is the value of cos c
Tomtit [17]

Answer

cos c = 40/41


Step by step explanation

It is a right triangle.

AB^2 + BC^2 = AC^2

9^2 + 40^2 = 41^2

81 + 1600 = 1681

1681 = 1681

Cos C = Opposite/Hypotenuse

Cos C = 40/41             [opposite = 40 and Hypotenuse = 41]

Thank you.

3 0
3 years ago
Read 2 more answers
With gasoline prices increasing, drivers are more concerned with their cars’ gasoline consump- tion. For the past 5 years, a dri
polet [3.4K]

Answer:

The calculated chi -square  value =5.7356 Is less than12.01 at 0.1level of significance .

The null hypothesis is accepted.

The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

Step-by-step explanation:

<u>Step:-(1)</u>

Given data 28 25 29 25 32 36 27 24

Sample size 'n' = 8

mean of the sample (x⁻) = ∑x /n = \frac{28+ 25+ 29 +25 +32 +36 + 27 + 24}{8}

mean of the sample (x⁻) =  28.25

x                           x- x⁻                         (x-x⁻ )²

28              28 - 28.25  = -0.25       0.0625    

25             25 -28.25   = -3.25       10.56

29             29-28.25    = 0.75        0.5625

25             25-28.25    = -3.25      10.56

32             32-28.25    =   3.75      14.06

36            36-28.25    =   7.75      60.06

27            27-28.25    = -1.25      1.5625

24            24-28.25    = -4.25      18.06

                                          ∑(x-x⁻)² =   115.4875    

<u>Step:-(2)</u>

The sample standard deviation

           S² = ∑(x-x⁻)²/n-1 = \frac{115.4875 }{7}  = 16.49

   By using χ² distribution

                           χ²  = \frac{ns^2 }{variance}

By above test can be applied only if the population from which sample is drawn normal.

Given data For the past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

Population variance σ² = 23

<u>Step:-(3)</u>

Null hypothesis :H₀:σ² = 23

Alternative hypothesis :H₁:≠23

X^{2} = \frac{8 (16.49)}{23}=5.7356

<u>The calculated chi -square  value =5.7356</u>

The degrees of freedom γ=n-1 =8-1=7

The tabulated value of chi -square = 12.01 at 0.1level of significance (check table)

The calculated chi -square  value =5.7356 Is less than12.01 at 0.1level of significance .

The null hypothesis is accepted.

<u>Conclusion</u>:-

The null hypothesis is accepted.

The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

                       

5 0
3 years ago
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