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3 years ago

What is the equation of a line that is perpendicular to - x + 2y = 4 and passes through the point (-2,1)

1 answer:

3 0

Perpendicular has slope that multiplies to -1

the slope for ax+by=c is -a/b
-1x+2y=4
slope=-(-1)/2=1/2
1/2 times what=-1?
-2

y=mx+b
m=slope
we need slope is -2
y=-2x+b
find b
given
(-2,1)
(x,y)
x=-2 and y=1 is a solution

1=-2(-2)+b
1=4+b
mius 4 both sides
-3=b

y=-2x-3 is equation

first one

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Find the difference of 1/2 - 3/11

TEA [102]

1/2 - 3/11

Set both denominators (bottom numbers) to 22, so multiply the numerator of 1/2 by 11, and multiply the numerator of 3/11 by 2.

1/2 is now 11/22

3/11 is now 6/22

So, our new question is now : 11/22 - 6/22

Because the denominators are the same, all you have to do is simplify the top numbers.

So, 11-6 = 5

Therefore, your answer is 5/22

~Hope I helped!~

3 0

3 years ago

Read 2 more answers

A shelter kept track of the number of dogs adopted each day for three weeks. Use the table to find the statistical measures.

maria [59]

Answer:

Mean: 6.29

Median: 7

Mode: 8

Range: 6

Step-by-step explanation:

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6 0

3 years ago

What is the factored form of the quadratic expression x^2+36

e-lub [12.9K]

Answer:

(x − 6i) (x + 6i)

Step-by-step explanation:

Using real numbers, x² + 36 is already simplified.

Using imaginary numbers:

x² + 36

x² − 36i²

(x − 6i) (x + 6i)

6 0

3 years ago

Solve the inequality.<br><br> 5/6t - 3≥3t + 6

Papessa [141]

Answer:

t ≤ $-\frac{54}{13}$

Step-by-step explanation:

$\frac{5}{6}$ t−3−3t≥3t+6−3t

$-\frac{13}{6}$ t−3≥6

- $\frac{13}{6}t$ −3+3≥6+3

$\frac{13}{6}$ t≥9

$-\frac{6}{13}$ ( $-\frac{13}{6}$ t) ≥ $-\frac{6}{13}$ (9)

t ≤ $-\frac{54}{13}$

6 0

2 years ago

Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di

quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0

3 years ago