WHAT IS THE ANSWER TO THIS QUESTION?

A rectangle has sides measuring (2x + 7) units and (5x + 9) units. Part A: What is the expression that represents the area of th

andrey2020 [161]

Answer:

Part A:

(2x+7)(5x+9)

=(2x+7)(5x+9)

=(2x)(5x)+(2x)(9)+(7)(5x)+(7)(9)

=10x2+18x+35x+63

=10x2+53x+63

A)

The formula for determining the area of a rectangle is given as

Area = length × width

Given that the length and width are (2x + 6) units and (5x + 3) units, the expression for the area is

(2x + 6)(5x + 3) = 10x² + 6x + 30x + 18

Area = 10x² + 36x + 18

B)

The degree is 2 because the highest power of the terms is 2. It is classified as a trinomial because it has 3 terms.

C) it is closed under multiplication. the exponents in the polynomials are whole numbers(2 and 1). The whole numbers are closed under addition, which means that the new exponents formed are also whole numbers. The exponents were whole numbers before multiplication and doesn't change after multiplication.

Step-by-step explanation:

3 0

3 years ago

HELP NOW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Umnica [9.8K]

I think that it is B because I'm pretty sure it has to be log of 50,000. But I forgot how to get the rest of it but B is the only one with log of 50k.

6 0

3 years ago

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In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

3 years ago

What are the x-intercepts of x^2– 3x = 4?

Sindrei [870]

Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

3 0

3 years ago

What is Pythagoras Theorem ?

Nikitich [7]

Pythagoras Theorem is the way in which you can find the missing length of a right angled triangle.
The triangle has three sides, the hypotenuse (which is always the longest), Opposite (which doesn't touch the hypotenuse) and the adjacent (which is between the opposite and the hypotenuse).
Pythagoras is in the form of;
a<em><u /></em>²+b²=c²
However, it can also be written in the form of c²=a²+b²
In order to find the hypotenuse, you will have the length of two sides, for example, these could be 3 and 4.
As 'C' is always the hypotenuse, you have to work out the two other lengths, and you do this by squaring the numbers.
3²=9 and 4²=16.
As you're looking for C, you've got to add these together
9+16=25
As a²+b²=c², this means that the answer for C is the square root of 25.
√25= 5

Hope this has been able to help you :)

5 0

3 years ago

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