Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
the value of x is 8 cm.
<u>Step-by-step explanation:</u>
Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.
We have ,
the area of a circle = πr²
the outer circle area = 
the inside circle area = 
According to Question,
the outer circle area - the inside circle area = he shaded region
⇒ 
⇒ 
⇒ 
⇒
Therefore , the value of x is 8 cm.
Answer:
yes
Step-by-step explanation:
The four interior angles of a quadrilateral always add to 360<span>°, so the answer is 98</span>
Answer:
The domain will be all real numbers, range will be all real numbers below -3
Step-by-step explanation:
its quadratic so it goes forever left and right. but the vertex has a y value of -3. It is a negative sloped graph, so anything below that is in the range
