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Katyanochek1 [597]
3 years ago
15

A total of $37185 is invested at an annual interest rate of 2% compounded quarterly. Find the balance after 11 years.

Mathematics
1 answer:
vazorg [7]3 years ago
8 0
A=37,185×(1+0.02÷4)^(4×11)
A=46,309.97
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The function f(x) = 16,800(0.9)x represents the population of a town x years after it was established. What was the original pop
Setler79 [48]

I am guessing that the correct form of equation is:

f(x) = 16,800(0.9)^x
where x is the exponent of (0.9)  

Since we are looking for the original population and x stand sfor the number of years, therefore x=0
substituting:
f(x) = 16,800(0.9)^0

Since (0.9)^0  would just be equal to 1. Therefore the original population is 16,800. 

 

Answer: B. 16,800

3 0
3 years ago
Read 2 more answers
NEEEEEEDDDDD HELP ASAP
mash [69]
The correct answer is that there is more variability in the heights of the volleyball team members.

The mean absolute deviation shows us how spread out the data is, so the larger the mean absolute deviation the higher the variability.

Both teams have players that are 76 inches tall, so the last two statements cannot be true.
6 0
3 years ago
Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the
mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ ,  μ₀ + σ]   contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ ,  μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ]   ⇒  [ 78 - (0,5)*8 , 78 + (0,5)*8 ]  ⇒[ 74 , 82]

[ μ₀ - σ ,  μ₀ + σ]  ⇒ [ 78 - 8 , 78 +8 ]   ⇒  [ 70 , 86 ]

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]  ⇒ [ 78 - 12 , 78 + 12 ]  ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]    ⇒  [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7  = 0,3 %

Only 0,3 % of population is out of   μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0
3 years ago
There are 515 students who attend central middle school. Three out of every 5 students live within 1 mile of the school. How man
AleksandrR [38]

Answer:

103 students live 1 mile away from the school.

Step-by-step explanation:

First dicide what the problem is really asking you then you end up getting divisoin them divide 515/3.

5 0
3 years ago
Please help , 1-10 , thanks !
PSYCHO15rus [73]

Answers:

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6 0
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