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quester [9]
3 years ago
8

If s = 1 over 3 unit and A = 54s2, what is the value of A, in square units? ____ square unit(s). (Input whole number only.) Nume

rical Answers Expected!
Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0
Subsitute for s and do the arithmetic.
.. A = 54s²
.. A = 54(1/3)² . . . . put 1/3 where s is
.. A = 54(1/9)
.. A = 6 . . . . . . square units
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A line passes through the points (–1, 10) and (3, 2). Which shows the graph of this line?
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Answer:

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Step-by-step explanation:

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4 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
3 years ago
a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times
diamong [38]

<em>Answer:</em>

<em>The perimeter of the larger square is 150cm.</em>

<em>Step-by-step explanation:</em>

<em>First of all, let one part of it be "x"</em>

<em>and the other part of it "200-x"</em>

<em>Now to solve this :</em>

<em>The area of the square = L^2</em>

<em>The area of one part of the square = x^2</em>

<em>The area of the other part of the square = (200-x)^2</em>

<em>9x^2= (200-x)^2\\9x^2=40000-400x+x^2</em>

<em></em>

<em>Now, add, -4x^2 to both the sides :</em>

<em>9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0</em>

<em />

<em>Now, take out the "8" which is common :</em>

<em>-8(x^2+50x-5000)=0</em>

<em></em>

<em>Now, divide it by -8 :</em>

<em>x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\</em>

<em>x=-100 or 50</em>

<em />

<em>So, now we know that :</em>

<em>One of the part is = 50cm</em>

<em>And the other part is = 150cm</em>

<em />

<em>Thus the perimeter of the larger square is = 150cm</em>

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scZoUnD [109]
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