Answer:
And replacing we got:
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.327;0.413).
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
The confidence interval would be given by this formula
Assuming a 95% of confidence. For the 95% confidence interval the value of and , with that value we can find the quantile required for the interval in the normal standard distribution.
The margin of error would be:
And replacing we got:
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.327;0.413).
The answer is 8.25 units
I took the test :)
Answer:
and let's then do away with the denominators, by multiplying both sides by the LCD of all fractions, in this case, the LCD will be 8, and then we'll combine the like-terms, but anyway, let's proceed.
Step-by-step explanation:
Answer:
-5F + 34* = 29*F
Step-by-step explanation:
Have a nice day! :-)
Answer:
Step-by-step explanation: