Answer:
15
Step-by-step explanation:
a² + b² = c²
9² + 12² = c²
81 + 144 = c²
c² = 225
c = 15
This requires the Poisson distribution, where
area = 5-acres
and mean number of field mice = 12 (in 5-acres of field)
therefore
lambda=12 (mean, given)
and the probability of k mice in the 5-acre field is given by the Poisson distribution as
P(X=k)=lambda^k * e^(-lambda) / k! ..............(1)
To find the probability of having LESS than 7 field mice, we add the probabilities of 0 to 6, which is
P(X<7)=P(X=0)+P(X=1)+...+P(X=6)
evaluating with equation (1) for X=0 to 6, we get:
0 0.0000061 0.0000742 0.0004423 0.0017704 0.0053095 0.0127416 0.025481Total = 0.045822
Answer: The probability that fewer than 7 field mice are found in the 5-acre field is 0.0458.
Answer:
361.27 Pound sterling
Step-by-step explanation:
F + V = E + 2
F = 25
V = 17
25 + 17 = E + 2
42 = E + 2
42 - 2 = E
40 = E <== there are 40 edges
Given: Security Service Company:
1.4 1.8 1.6 1.7 1.5 1.5 1.7 1.6 1.5 1.6
Mean: 1.59
Standard Deviation: 0.014333
Other companies: 1.8 1.9 1.6 1.7 1.6 1.8 1.7 1.5 1.8 1.7
Mean: 1.71
Standard deviation: 0.014333
The coefficient of variation for security Service Company:
CV = (Standard Deviation/Mean) * 100.
= (0.14333/1.59) * 100
= 9.01%
The coefficient of variation for other companies:
CV = (Standard Deviation/Mean) * 100.
= (0.014333 / 1.71) * 100
= 8.38%
the limited data listed here show evidence of stealing by the security service company's employees because there is a significant difference in the variation.
