Answer:
this an example not the answer i don't know the answer
E is between D and F.
Given: E is between D and F
Prove: DE = DF − EF.
Statements Reasons
1. E is between D and F Given
2. D, E, and F are collinear points, and E is on ¯DF Definition of between
3. DE + EF = DF Segment Addition Postulate
4. DE = DF − EF Subtraction property of equality
2. If →BD divides ∠ABC into two angles, ∠ABD and ∠DBC, then m∠ABC = m∠ABC - m∠DBC.
Step-by-step explanation:
M<2 = 90 - 50 = 40
answer
40 - last choice
It is hard to tell your precise intention. Choose the appropriate interpretation.
The two angle measures are equal (which is the point of an angle bisector), so you have
y + 30 = 3y - 50
30 = 2y - 50 . . . . . . . . subtract y
80 = 2y . . . . . . . . . . . . add 50
40 = y . . . . . . . . . . . . . .divide by the coefficient of y
The value of y is 40.
<h3>
Answer: Choice B) 15x, -x, and 33x</h3>
=========================================================
Explanation:
Like terms are when we have the same variable attached to the number. The variable must have the same exponent as well.
For instance, 2x and 3x are like terms since they both have x. Something like 7x and 8x^2 are not like terms because the exponents don't match.
Terms like 17y and 17 are not like terms because the second term doesn't have a y tacked on. If you have nothing but constants, then those are like terms as they all have the same thing in common in that they don't have a variable attached to them.
With all this in mind, we can see that 15x, -x, and 33x is the answer since each have x as part of the variable term. The exponents are all the same (all being 1).
