3 years ago

Really need help with this problem. Picture included

1 answer:

8 0

The two angle measures are equal (which is the point of an angle bisector), so you have
y + 30 = 3y - 50
30 = 2y - 50 . . . . . . . . subtract y
80 = 2y . . . . . . . . . . . . add 50
40 = y . . . . . . . . . . . . . .divide by the coefficient of y

The value of y is 40.

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A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?

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<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

Solution:

The volume of triangular prism is given as:

$v = base\ area \times height$

Given that,

A triangular prism container is full of water of 428 cubic cm

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v = 428 cubic cm

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Substituting the values we get,

$428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2$

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