The value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
<h3>How to evaluate the expression?</h3>
The expression is given as:
3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two
Rewrite properly as:
[3² * 3⁻⁵]/[5⁻²]
Apply the negative exponent law of indices
So, we have
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]
Apply the exponent law of indices
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]
This gives
[3² * 3⁻⁵]/[5⁻²] = 25/27
Hence, the value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
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Chupapi Minton eisisisjenensjzjdjdjejsjsjzjzusss
The law of cosines states that:
c^2=a^2+b^2-2abcosC
You already have all the values for the variables with the exception of x so:
x^2=25+100-100cos60
x=√(125-100cos60)
x=√75
x≈8.66 to nearest one-hundredth...
Answer:
4 ft downwards
Step-by-step explanation:
old height off the ground :
7^2+b^2=25^2
49+b^2=625
b^2=576
b=24
new height off the ground :
7+8=15
15^2+ b^2 =25^2
225+b^2 = 625
b^2 = 400
b=20
difference between heights :
24 - 20 = 4
Answer:
150 mL
Step-by-step explanation:
We need a mixture that is at 50%, now we have 200 mL at 35% and another mixture that is at 70%, that is, we must calculate how much of this mixture is added, by the following equation
200 * 35% + x * 70% = 50% (x + 200)
70 + 0.7 * x = 0.5 * x + 100
0.7 * x - 0.5 * x = 100 - 70
0.2 * x = 30
x = 30 / 0.2
x = 150
150 mL must be added so that the mixture is 50%.
