Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
The slope of the line, is the one with an variable, in this case x. The other value, 27.52, is the y intercept, which would represent how much money he began with. So the variable 17.63x represents how much he could expect to make per week. We know it is per week because there is only a single x, if there were two x's it would be per 2 weeks, three x's per 3 weeks and so on.
From this we can conclude the answer is B, Aidan can expect to save about $17.63 each week
22x12x5 and you will get the answer
Answer:
x = 2, y = 1
Step-by-step explanation:
x + 4y = 6 and y = 3 - x have to be rearranged: x + 4y = 6 and x + y = 3
You subtract the equations to eliminate one of the variables (x) so that the other can be found
The velocity of the particle is given by
Since 
and 
, we get
Similarly, the position function is obtained via
We know 
and we're told that 
, so
making the answer A.
