In order to find the slope of line that passes through 2 points, use the equation slope=rise/run
rise = 5-(-4) =9
run = 2- 0 =2
slope = rise/run = 9/2

5 0

3 years ago

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What is sin 0 when sec 0 = 5? 0 |(1,0) sin e = 2[?] [] Rationalize the denominator if necessary.

Komok [63]

Answer:

$Sin ~0 =\frac{2\sqrt{5} }{5}$

Step-by-step explanation:

$sec0=\sqrt{5}$

$cos~0=\frac{1}{sec0} =\frac{1}{\sqrt{5} }$

$sin ~0=\sqrt{1-cos^2~0}$

$=\sqrt{1-1/5}=\sqrt{5-1/5}$

$Sin~0=\sqrt{4/5} =2/\sqrt{5}*\sqrt{5}/\sqrt{5}$

$Sin~0=2\sqrt{5}/2=2\sqrt{5}/5$

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hope it helps...

have a great day!!!

7 0

3 years ago

Find the equation of the line passing through the points (5,3) and (5,−6).

allsm [11]

Answer:

In y-intercept form: X = 5

Step-by-step explanation:

$(\frac{-6-3}{5-5} ) = \frac{-9}{0}$

Becuz the slope is Undefined

7 0

3 years ago