We are going to consider a rectangle with length called "a" and width "b" Then we know that perimeter is the sum of both sides 2*a + 2*b = 128 And also the following equation given by the question: a = 2*b + 3 So solving the first equation: 2*(2*b+3) + 2*b = 128 4*b+6+2*b=128 6*b = 122 b = 122/6 = 61/3 Then a=2*122/6+3 = 244/6+3 = 262/6 = 131/3 Solution: Length = 131/3 Width = 61/3
what is ur choices to choose from?
the answer I got was 6 (x-5)
let me know if this is right or not
Answer:
C D
Step-by-step explanation:
Answer:
B.) 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
x - y = -1
3x + 5y = 21
<u>Step 2: Rewrite Systems</u>
x - y = -1
- Add <em>y</em> to both sides: x = y - 1
<u>Step 3: Redefine Systems</u>
x = y - 1
3x + 5y = 21
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 3(y - 1) + 5y = 21
- Distribute 3: 3y - 3 + 5y = 21
- Combine like terms: 8y - 3 = 21
- Add 3 to both sides: 8y = 24
- Divide 8 on both sides: y = 3