Please help thanks :)

Has the marrying age of a man changed over the years? The United States Bureau of the Census takes a formal count of everyone in

ch4aika [34]

The answer to your question is B

5 0

2 years ago

The point (0,0) is a solution to which of these inequalities?

Gre4nikov [31]

It is the solution for B

3 0

3 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

8 0

3 years ago

On a long distance bike trip Annike started at 7 a.m and her average speed was 11 miles per hour and Celia travels 14 miles per

Troyanec [42]

Answer:

Annike's bike trip started at 7:00, if she and Celia both start at the same time you would multiply Annike's average speed by Celia's average speed to find where they would have completed the same number of miles

equation: 11×14=154 14×11=154

Step-by-step explanation:

counting by 11:

11 22 33 44 55 66 77 88 99 110 121 132 143 154

11 × 14 = 154

counting by 14:

14 28 42 56 70 84 98 112 126 140 154

14 × 11 = 154

8 0

3 years ago

1/4Wpw ww - 1/4BbwBwv - 1/4Ga Vw Gap WTH help plz

Dima020 [189]

Answer:

Can you explain the question lol in so confused

Step-by-step explanation:

8 0

2 years ago