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inysia [295]
1 year ago
15

In a 24 marathon, solve the 24 puzzle given by the poster above you, and post a new 24 puzzle of your own!

Mathematics
2 answers:
Black_prince [1.1K]1 year ago
7 0
1234567891011121314151617181920
12345 [234]1 year ago
4 0

Answer:

At Less In Number 20

Step-by-step explanation:

1234567891011121314151617181920

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The slope-intercept form of a linear equation is y=mx + b, where x and y are
HACTEHA [7]

Answer:

m = \frac{y-b}{x}

Step-by-step explanation:

Given

y = mx + b ( isolate the term in m by subtracting b from both sides )

y - b = mx ( divide both sides by x )

\frac{y-b}{x} = m

6 0
3 years ago
Which of the following is not a way to represent the solution of the inequality 8x - (5x + 4) greater than or equal to -31?
n200080 [17]
The response is 
<span>x greater than or equal to -9
</span>proof
8x - (5x + 4)>= -31, 3x- 4>= -31, 3x >= -27,  <span>x>= -27/3= -9
so </span><span>x greater than or equal to -9</span>
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3 years ago
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Please answer this multiple choice question only if you know the answer!! 25 points and brainliest!
solniwko [45]

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i cant see it

Step-by-step explanation:

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2 years ago
WILL MARK BRAINLIEST HELP ME PLEASE
PolarNik [594]
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4 0
3 years ago
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Apply Newton’s method to estimate the solution of x3 − x − 1 = 0 by taking x1 = 1 and finding the least n such that xn and xn +
ss7ja [257]

Solution :

Given

$f(x)=x^3-x-1, x_1=1$

$f'(x)=3x^2-1$

Let the initial approximation is $x_1 =1$

So by Newton's method, we get

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)},n=1,2,...$

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}=1-\frac{1^3-1-1}{3(1)^2-1}=1.5$

$x_3=1.5-\frac{(1.5)^3-1.5-1}{3(1.5)^2-1}=1.34782608$

$x_4=1.34782608-\frac{(1.34782608)^3-1.34782608-1}{3(1.34782608)^2-1}=1.32520039$

$x_5=1.32520039-\frac{(1.32520039)^3-1.32520039-1}{3(1.32520039)^2-1}=1.32471817$

$x_6=1.32471817-\frac{(1.32471817)^3-1.32471817-1}{3(1.32471817)^2-1}=1.32471795$

$x_5 \approx x_6$ are identical up to eight decimal places.

The approximate real root is x ≈ 1.32471795

∴ x = 1.32471795

4 0
3 years ago
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