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Ganezh [65]
2 years ago
15

What would y=-5x+25 look like on a graph? When you find out, please give me an image.​

Mathematics
1 answer:
Gekata [30.6K]2 years ago
6 0

Answer:

Step-by-step explanation:

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Maria consumed 1.75 gallons of water in one day. how many milliliters are equal to 1.75 gallons?
gregori [183]

Answer:

6624.471 millilitres

(btw i love the pfp)

5 0
3 years ago
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How to find the height of a cube in terms that a 12 year old can know pls
kolbaska11 [484]

Answer:

To find the height of a cube you simply need to know the length of the sides of a cube.

Step-by-step explanation:

All sides of a cube are equal because it is made up of squares. If a cube has a length of 3 cm, then it will also have a height of 3 cm.

6 0
2 years ago
Need help geometry question central angles and arcs
antiseptic1488 [7]

Answer:

the answer is 45 degrees

6 0
3 years ago
What is the area of the shaded region?
Verdich [7]
<h2>Area of Composite Shapes</h2>

To find the area of composite shapes, we can break the bigger shape down into small, simpler shapes, and find the sum of their areas.

For this triangle, we will need to know the formula to find the area of a triangle:

A=\dfrac{1}{2}bh

<h2>Solving the Question</h2>

The given shape can be seen as one large triangle with a little triangle cut out of it. To find the shaded region, we can:

  1. Find the area of the large triangle
  2. Find the area of the little triangle
  3. Subtract the area of the little triangle from the large triangle

<h3>Area of the Large Triangle</h3>

A=\dfrac{1}{2}bh

⇒ Plug in the values given for the base and height:

A=\dfrac{1}{2}(5)(2+4+6)\\\\A=\dfrac{1}{2}(5)(12)\\\\A=(5)(6)\\\\A=30 mm^2

<h3>Area of the Small Triangle</h3>

A=\dfrac{1}{2}bh

⇒ Plug in the values given for the base and height:

A=\dfrac{1}{2}(3)(4)\\\\A=(3)(2)\\\\A=6mm^2

<h3>Subtract the Area of the Small Triangle from the Area of the Large Triangle</h3>

30 mm^2-6mm^2\\=24mm^2

<h2>Answer</h2>

The area of the shaded region is 24mm^2.

5 0
2 years ago
Match the following items by evaluating the expression for x = -6.
Kryger [21]

Step-by-step explanation:

Put the value of x = -6 to all expressions:

x^{-2}=(-6)^{-2}=\dfrac{1}{(-6)^2}=\dfrac{1}{6}\qquad\text{used}\ a^{-n}=\dfrac{1}{a^n}\\=====================\\x^{-1}=(-6)^{-1}=\dfrac{1}{(-6)^1}=-\dfrac{1}{6}\\=====================\\x^0=(-6)^0=1\qquad a^0=1\ \text{for all real numbers except 0}\\=====================\\x^1=(-6)^1=-6\qquad a^1=a\ \text{for all real numbers}\\=====================\\x^2=(-6)^2=36

5 0
3 years ago
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