What would y=-5x+25 look like on a graph? When you find out, please give me an image.
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We are given parabola equation y=x^2-10x+30.
We need to convert it in vertex form y= a(x-h)^2+k.
We need to find the value of a, h and k to get the vertex form.
For the given equation y=x^2-10x+30, the coefficient of x^2 is 1.
Therefore, a=1.
Now, let us find values of h and k.
h = -b/2a.
h = -(-10)/2(1) = 5.
Plugging x=5 in given equation to get the value of k.
y= x^2-10x+30 => (5)^2 -10(5) +30 = 25 -50 +30 = 5.
Therefore, k =5.
Therefore, vertex (h,k) = (5,5).
<h3>So, the vertex form is </h3>On the number line, 3 and 11 are the numbers that are a distance of 4 units from 7..
On there are two types of numbers one is a positive and the other is a negative number. These two are separated by the number zero which is known as the origin. Positive numbers are on the right side of the origin and negative numbers are on the left side of the origin on the number line.
We have been asked the numbers which are a distance of 4 units from 7 on the number line.
For that, we will first add 4 to the number 7, that is,
4 + 7 = 11
Thus, number 11 is a distance of 4 units from 7 on the number line if we move to the right side from 7.
Now we will subtract 4 from the 7 we will get,
7-4 = 3
Thus, Number 3 is a distance of 4 units from 7 on the number line if we move to the left side from 7.
Hence 3 and 11 are the numbers that are a distance of 4 units from 7 on the number line.
Learn more about the number line here: brainly.com/question/77754
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