Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)
we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5
slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1
slope=-1
The graph of a function is linear of the graph is a straight line.
For 4x^2y over 2x^8y^4 try 2 over x^6y^3
The answers to the questions are
- The mathematical model is given as s = −16t2 + 1054
- The height after 4.5 seconds is 730 feet
- the time it would take to strike the ground is 8.11 seconds.
<h3>How to solve for the position of the object</h3>
The mathematical model of this problem would be written as
s = −16t2 + v0t + s0
s0 = 1054
then we would have
s = −16t2 + 1054
b. after 4.5 seconds the height is going to be
s = −16t2 + 1054
= −16(4.5)² + 1054
= -16 * 20.25 + 1054
= 730
C. the time that it takes to strike the ground
s = −16t² + 1054
= 16t² = 1054
t² = 1054/16
= 65.88
t = √65.88
t = 8.11
Hence the time it would take to strike the ground is 8.11 seconds.
Read more on velocity here:
brainly.com/question/4931057
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Part 1:
180 = 5p+98 + 9p-2
180 = 14p + 96
84 = 14p
6 = p
part 2:
angle S will be the same as angle Q, so:
9p-2
9(6)-2
54-2
M
