Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Answer:
9 boxes cost Rs 405
Step-by-step explanation:
1 box costs 45.
so, how much are 2 boxes ? what do you think ?
right, twice as much : 2 × 45 = 90
how much are 3 boxes ?
now it is three times the cost of 1 box : 3 × 45 = 135
do you see the pattern ?
it is really simple.
that is also the origin why we describe a multiplication by "times". we take a single item so and so many times.
when you see something like this, you know, they are talking about multiplication.
so, here we want to know how much 9 boxes cost.
therefore,
9 × 45 = 405
is the answer.
The answer would be A and C.
Hope this helps!<3
First row, the answer on the left , -5 3/4 - 4 2/3
