Answer:
Determine the parental genotypes. You can use any letter you like but select one that has a clearly different lower case, for example: Aa, Bb, Dd.
Split the alleles for each parent and add them into your Punnett square around the edges.
Work out the new possible genetic combinations inside the Punnett square.
Explanation:
I believe it’s A. Not sure though
6÷0........ There is no answer to that really 0 is nothing in numbers so I guess it would just stay 6. Know if it was 0÷6 it would be 0 be cause anything divide by zero will always equal 0
The complete question is attached to the answer.
Answer:
The correct hypothesis would be - the food (proteins) are not completely broken down in the intestine due to intestinal Protease production is lower than normal in Claire.
Explanation:
According to the image, we can find that the normal intestine fluid has the same pH as the pH of claire's Intestine fluid which is suitable for the breaking down of the food or protein in particular. It is also found that there is some amount of protein digested which suggests that there is no mutation in the active site.
According to the graph, claire is able to break down or digest the food completely if 1mg proteases enzyme is used so it proves the enzyme is produced less than normal. On the basis of this information, the correct hypothesis would be -
"The food (proteins) are not completely broken down in the intestine due to intestinal Protease production is lower than normal in Claire."
Answer:
The offspring will also be white and homozygous.
Explanation:
If the two cats are white and homozygous where the gene B is for black color and dominant, gene b is for white color and recessive. In this case the genotypes of the two cats are going to be "bb" which can only lead to the same genotypes and phenotypes in their offspring. They will also be white and homozygous.
I hope this answer helps.