Answer:
In a fruit fly experiment, grey body, normal winged (homozygous dominant) fruit flies were mated with black body, short winged (homozygous recessive) fruit flies. The F1 dihybrid females were then used in a test cross. If the genes are always linked and no crossing over occurs, what would be the predicted ratio in the F2 generation?
GG x bb = Gb, Gb, Gb and Gb F1 generation
grey body heterozygous offspring 4:0
Gb x Gb= GG, Gb, Gb, and bb F2 generation
3:1 three grey body fly and one black body fly
Explanation:
We are asked to fill up the blank space provided by the question above. The question above state that "<span>At higher doses, __________ causes twitching, irritability, panic, heart attack, and death." The statement talks about a term used when a person suffer such characteristics. The nearest term to described conditions once used by a person is called Cocaine.</span>
Answer:
D: 4.6 x 
Explanation:
4.6 x 10^{9} = 4,600,000,000
Earth is approximately, 4.6 billion = 4,600,000,000 = 4.6 x 10^{9}
Answer:
Explanation:
a. Since both the parents are carriers, they have one allele that is the gene for the normal trait and one gene that is for the sickle cell trait. So the genotypes of the parents are Hh
b. If we use a punnett square:
H h
H HH Hh
h Hh hh
Genotypic ratio: 1 HH: 2Hh: 1hh
Phenotypic ratio: 1 normal blood cell: 2 sickle cell carriers: 1 sickle cell disease