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Minchanka [31]
3 years ago
9

387.2 miles in 8 hours miles per hour

Mathematics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:

48.4 hours

Step-by-step explanation:

Time = Distance/Rate

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If one of the roots of the quadratice quation x2+kx-12=0is4,what is the value of k?
uysha [10]
<h3>Given Equation:</h3>

\huge \purple {\rm { {x}^{2}  + kx - 12 = 0}}

<h3>Value:</h3>

\huge \purple {\rm {x = 4}}

<h3>To Find:</h3>

\huge \purple {\rm {The \: value \: of \: k.}}

<h3>Solution:</h3>

\huge \purple {\rm { {(4)}^{2}  + k(4) - 12 = 0}}

\huge \purple {\rm {or, \: 16 + 4 k - 12 = 0}}

\huge \purple {\rm {or, \: 4k =  - 4}}

\huge \purple {\rm {or, \: k =  \frac{ - 4}{4}  =  - 1}}

<h2>Answer:</h2>

\huge \purple {\sf {The \: value \: of \: k \: is \: -1}}

3 0
3 years ago
Read 2 more answers
25 points and brainliest <br><br><br> How many hours,minute,seconds in 7 days
geniusboy [140]

Answer:

168 hours or 10080 minutes or 604800 seconds

Step-by-step explanation:

7days * 24 hours = 168 hours

168 hours * 60 minutes = 10080 minutes

10080 minutes * 60 seconds = 604800 seconds

7 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
what is an equation of the line that passes through (3-1) and is parallel to y = -4x + 1 in slope intercept form?
Agata [3.3K]
So we are given that the line passes through (3,-1)
also been given the parallel line, we can tell that the slope is -4
to make a slope intercept form equation...
y = -4x +11

Hope this helps :)
4 0
4 years ago
Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
nata0808 [166]
Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
L_x=2xy+1+\lambda y=0
L_y=x^2+1+\lambda x=0
L_\lambda=xy-5=0

\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x

\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}
xy=5\implies y=\pm\sqrt{30}

At these points, we get local minima of f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}.

- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x
\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}

and so on.
8 0
3 years ago
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