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____ [38]
2 years ago
14

3. MATCH is a regular pentagon with coordinates M(-1,1) and A(3,0). What is the perimeter of MATCH?

Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

Answer:

<h3>2.squareroot 85</h3>

Step-by-step explanation:

<h2>#carry on learning</h2><h2>#mark branlits</h2>
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A. Sydney invests $100 every month into an account that pays 5% APR
wlad13 [49]

Answer:

30 bucks .

Step-by-step explanation:

4 0
3 years ago
How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
polet [3.4K]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

3 0
3 years ago
PLEASE HELP ME
OleMash [197]

Answer:

wait do you still need the answer?

6 0
3 years ago
2. Which equation is equivalent to 2 + 4x = 5 - 3(x + 1)? A. 2 + 4x = 2x - 3 B. 2 + 4% = 5 - 3 -3. C. 6x = 5-(+ 1). D. 2 + 4 = 2
Andre45 [30]

Answer:

B) 2 + 4x = 5 - 3 - 3x

Step-by-step explanation:

By simplifying JUST the right side and re-arranging them

2 + 4x = 5 - 3(x + 1),

2 + 4x = 5 - 3x -3,

2 + 4x = 5 -3 - 3x

3 0
3 years ago
Given the quadratic function g(x)=x^2, find g(3x-2).
maxonik [38]

Answer:

g(3x-2) = (3x-2)^{2}

Step-by-step explanation:

g(x)=x^{2}

To do this, you must substitute 3x-2 for x in the equation g(x)

g(3x-2) = (3x-2)^{2}

Simplified this would be

9x^{2} -12x+4

7 0
3 years ago
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