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2 years ago

Can you help me with this

Mathematics

1 answer:

Sati [7]2 years ago

4 0

Answer:

The answer is b. 979,000

Step-by-step explanation:

If you move the decimal right five time from 9.79 you would get 979,000

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1100 students attend Ridgewood Junior High School. 20% of students bring their lunch to school everyday. How many students broug

Vlada [557]

Answer:

20% of 1100 is 220, so two hundred and twenty students brought their lunch to school on Thursday (and every other school day).

Step-by-step explanation:

The day of the week is a distraction. All you need to know is that 20% of 1100 students bring their lunch to school every day. 20% of 1100 is 200 + 20, or 220. So 220 students bring their lunch to school every day.

4 0

2 years ago

2. You need to work a total of 44 hours per week at your two jobs. Your job as a store clerk pays

vladimir2022 [97]

I think that the answer is second one

4 0

2 years ago

F(x) = 4x + 7, g(x) = 3x^2 Find (f + g)(x)

kondor19780726 [428]

For the functions f(x) = 4x + 7 and g(x) = -9x + 11, find f(g(0)). For the functions f(x) = 3x2 - 7 and g(x) = -3x2 + 4, find f(g(2)). (Do NOT put commas in large numbers.)

3 0

3 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

2 years ago

Jennie purchased 5 of the 200 tickets at the raffle. There will be two drawings for a prize.

vagabundo [1.1K]

Her chances for the drawings is 1/40 as if it was out of 100, it would be 1/20.

6 0

2 years ago