Answer:
x = 3
y = 5
Step-by-step explanation:
Using theorem of similar triangles, we have,
(6 + x)/6 = (7 + 3.5)/7
(6 + x)/6 = 10.5/7
Cross multiply
7(6 + x) = 10.5(6)
42 + 7x = 63
7x = 63 - 42
7x = 21
x = 21/7
x = 3
Thus:
7.5/y = (7 + 3.5)/7
7.5/y = 10.5/7
Cross multiply
7.5*7 = 10.5*y
52.5 = 10.5*y
Divide both sides by 10.5
52.5/10.5 = y
y = 5
The <em><u>correct answers</u></em> are:
60 pounds of onion rings and 60 hamburgers.
Explanation:
Jack serves a half pound of onion rings with every burger. He serves 120 bacon cheeseburgers. To find the number of pounds of onion rings, we multiply 1/2 pound by 120 burgers:
1/2(120) = 1/2(120/1) = (1*120)/(2*1) = 120/2 = 60 pounds of onion rings.
There were 8 hamburgers served out of the first 40 orders. If this rate continues, then to find the number of hamburgers out of 300 orders, we multiply 8/40 by 300:
8/40(300) = 8/40(300/1) = (8*300)/(40*1) = 2400/40 = 60
There would be 60 hamburgers.
Answer:
3.50
Step-by-step explanation:
Total Quality Points Gained= C=2, A=4,B=3 and A=4
Sum the Points 2+4+3+4 (4)=25
Average= Total Points/ Total number of courses
A=25/7=3.50
Answer:
x-15).8 this is the answer
Step-by-step explanation:
So say, we add "x" of the 60% saline solution, now, how much salt is in that solution? now 60% is salt but the rest is something else, but only salt is 60% of "x", or (60/100) * x, or
0.6x.
likewise, for the 10 Liters, if only 50% is salt, then is just (50/100) * 10 or
5.
now... let's check the water whilst we add "y" amount, the water has no salt at all, freshwater for that matter, so, salinity is 0%. or (0/100) * y or
0.
