7/6 is 1 and 1/6 (1 1/6) as a reduced fraction. 7/6 is an improper fraction. So, how many times does 6 go into 7, it goes into it one time and there is one remainder.
First integer = x
Second integer = x + 2
Third integer = x + 4
Since four times the first integer equals six more than the product of two and the third integer.
4x = 6 + 2(x + 4)
4x = 6 + 2x + 8
2x = 14
x = 7.
Hence,
First integer = x = 7
Second integer = x + 2 = 7 + 2 = 9
Third integer = x + 4 = 7 + 4 = 11.
hope this helps
Answer:
10
Step-by-step explanation:
AB = CD = 10, so AB = 10
Answer:
c and a are the correct answers
