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2 years ago

What is the sum of q and 8

Mathematics

2 answers:

mart [117]2 years ago

8 0

The word "sum" tells you that you have to add.

q+ 8

The sum of q and 8 is q+8~

Vera_Pavlovna [14]2 years ago

7 0

Is there any more information, such as the value of q? Otherwise the sum of q and 8 is q + 8 because "sum" indicates addition.

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Given the triangle below, tell me if it's a right triangle or not. Then, explain your answer with evidence.

padilas [110]

No because the triangle’s angle is less than 90 degrees if it was a right angle triangle it would have a square marking the angle.

6 0

3 years ago

When a jug is half-filled with marbles, it weighs 2.6 kg. If the jug weighs 4 kg when full, find the weight of the empty jug.

Soloha48 [4]

Let x be the jug, $\frac{1}{2}$ for half-filled, y for the weight of the jug when empty.

∵ $\frac{1}{2}$ x + y = 2.6 kg

∵ x = 4 kg

∴ $\frac{1}{2}$ ⋅ 4 + y = 2.6 kg

∴ 2 + y =2.6 kg

∵ y = 2.6 - 2 = 0.6 kg

∴ The weight of the empty jug = 0.6 kg

8 0

2 years ago

Read 2 more answers

Multiple choice please help!!

AveGali [126]

3 and 4

Step-by-step explanation:

y=5x

y=5(0)

y=0

y=5x

y=5(10)

y=50

y=5x

y=5(51)

y=255

y=5x

y=5(400)

y=2000

5 0

2 years ago

8 (p + 8 7 + 2q)<br><br> help me pleas!!!

77julia77 [94]

Answer:

8p +56 +16q

Step-by-step explanation:

8 (p+7+2q)

If we distribute the 8 into everything in the parenthesis, we get:

8p +56 +16q

5 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

Read 2 more answers