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jolli1 [7]
3 years ago
6

A box of cereal states that there are 96 calories in a 3/4 cup serving. What is the unit rate for calories per cup? how many cal

ories are there in 3 cups of the cereal?
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0
Divide 96 w/ 3 you get 32 multiply 32x4 you get 128 multiply 128x3 and the answer is 384
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How do you graph y equals 3 over 2x -4
lesya692 [45]

Answer:

Step-by-step explanation:

3/2 is the slope in y=mx+b format

b= y-intercept witch would be -4 sense it is subtracting not adding

m=slope witch is 3/2

x=x-axis

8 0
3 years ago
What is 32/144 in simplest form?
Arturiano [62]
2/9 is 32/144 in simplest form
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What is 2 and 41/50 as a percent
Vitek1552 [10]
2 and 41/50 as a percent is 282%.
7 0
3 years ago
Read 2 more answers
A principal of $2900 is invested at 4.25% interest, compounded annually. How much will the investment be worth after 7 years?
olga2289 [7]

Let S = Sum after 13 years

     So = amount invested

     t = time in years

     i = annual interest rate = .0325

The S = So(1+i)t = $2,200(1.0325)13 = $3,334.21

4 0
2 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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