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ss7ja [257]
3 years ago
9

A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then

a second marble is drawn.
a. What is the probability of selecting a purple marble and then a white marble?

b. What is the probability of selecting two white marbles?

c. Is there a greater chance of selecting two white marbles in a row or two purple marbles in a row? Sho your work.

PLEASE I REALLY NEED HELP AND NO ONE HAS BEEN ASNWERING MY QUESTIONS! I AM GIVING TEN POINTS TO ANYONE JUST PLEASE!
Mathematics
2 answers:
Masja [62]3 years ago
6 0
A.
\frac{7purple}{9total} *  \frac{2white}{8total}  \\  \frac{14}{72}  \\ =0.194
The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.
\frac{2white}{9total} *  \frac{1white}{8total}  \\  \frac{2}{72}  \\ =0.278
The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
<u />\frac{7purple}{9total} *  \frac{6purple}{8total}  \\  \frac{42}{72}  \\ =0.583
Chance of selecting two white marbles:
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
<u>Chance of selecting two purple</u> vs. <em>Chance of Selecting 2 white:</em>
<u>0.583</u>><em>0.278</em>.
It is more likely to select 2 purple marbles.

Hope this helps!
jolli1 [7]3 years ago
6 0

this person is correct yes yes yes yes yes

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Alright, lets get started.

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In an arithmetic series, the sum of the first 12 terms is equal to ten times the sum of the first 3 terms. If the first term is
arlik [135]

Answer:

Step-by-step explanation:

The formula for determining the sum of the first n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

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Also, the expression for the sum of the first 3 terms is

S3 = 3/2[2 × 5 + (3 - 1)d]

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The sum of the first 12 terms is equal to ten times the sum of the first 3 terms. Therefore,

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60 + 66d = 150 + 30d

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S20 = 10[10 + 47.5)

S20 = 10 × 57.5 = 575

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3 years ago
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