Answer:
Looking at the graphic, if a 45-45-90 triangle has a hypotenuse of 1, then each of the side lengths equal 1 / square root (2)
Source: https://www.1728.org/trig2.htm
Step-by-step explanation:
Answer:
Factors of kmn are 1, k, m, n, km, mn, kn and kmn
Step-by-step explanation:
Given: k, m, and n are prime numbers
To find: factors of k∙m∙n
Solution:
A number is said to be prime if it has exactly two factors: 1 and the number itself
x is said to be a factor of y if x can divide y exactly.
Here,
1 can divide kmn
k can divide kmn
m can divide kmn
n can divide kmn
km can divide kmn
kn can divide kmn
mn can divide kmn
kmn can divide kmn
So, factors of kmn are 1, k, m, n, km, mn, kn and kmn
Given:
The equation of a line is:

A line passes through the point (-5,-3) and perpendicular to the given line.
To find:
The equation of the line.
Solution:
Slope intercept form of a line is:
...(i)
Where, m is the slope and b is the y-intercept.
We have,
...(ii)
On comparing (i) and (ii), we get

We know that the product of slopes of two perpendicular lines is always -1.



Slope of the required line is
and it passes through the point (-5,-3). So, the equation of the line is:



Using distributive property, we get




Therefore, the equation of the line is
. Hence, option A is correct.
Answer:5r2+2
Step-by-step explanation:
Distribute the Negative Sign:
=4r2−3r+2+−1(−r2−3r)
=4r2+−3r+2+−1(−r2)+−1(−3r)
=4r2+−3r+2+r2+3r
Combine Like Terms:
=4r2+−3r+2+r2+3r
=(4r2+r2)+(−3r+3r)+(2)
=5r2+2
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16