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shutvik [7]
3 years ago
6

Motorway cafe pie charts

Mathematics
1 answer:
marta [7]3 years ago
6 0
For #1: 
 look at the chart and write the percentages that are by the name of the food and write the percentages next to the names

For #2:
 take the percentage number and divide it by 2 (because it was 50 customers out of 100%) for example if 50% of the customers picked apples then divide it by 2 and 25 customers would have gotten apples and put that number next to the name

 Hope that helps :D
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The graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.
marshall27 [118]

Please consider the graph.

We have been given that graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.  We are asked to choose the weights, which are within 2 standard deviations of the mean.

We can see from our graph that mean of the weights is 9.5 and standard deviation in 0.5.

The data point that would be below two standard deviation is: 9.5-2\times 0.5 that is 9.5-1=8.5.

The data point that would be above two standard deviation is: 9.5+2\times 0.5 that is 9.5+1=10.5.

Now we need to check the data points that lie within 8.5 and 10.5.

Upon looking at our given choices, we can see that 8.9, 9.5 and 10.4 pounds lie within 2 standard deviation of the mean.

Therefore, 8.9 lbs, 9.5 lbs and 10.4 lbs are correct choices.

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Which property can be justified using the ratios in triangle XYZ
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This is C. cos Z = sin (90 - Y)
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What is n/8=11/5 solve for n<br><br><br> #youngboy comment
mihalych1998 [28]

n should be 8 according to mathmatical laws

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How do I solve this quadratic equations by factoring
Aleks [24]
If xy=0, assume that x and/or y=0

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therfor
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7 0
4 years ago
Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha
Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

a = 20 --- tree distance from north gate

b =14 --- movement from south gate

c = 1775 --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

\triangle ADE \sim \triangle ACB --- similar triangles

So, we have the following equivalent ratios

AE:DE = AB:CB

Where:

AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775

Substitute these in the above equation

20:x/2 = 20 + x + 14: 1775

20:x/2 = x + 34: 1775

Express as fraction

\frac{20}{x/2} = \frac{x + 34}{1775}

\frac{40}{x} = \frac{x + 34}{1775}

Cross multiply

x *(x + 34) = 1775 * 40

Open bracket

x^2 + 34x = 71000

Rewrite as:

x^2 + 34x - 71000 = 0

Expand

x^2 + 284x -250x - 71000 = 0

Factorize

x(x + 284) -250(x + 284)= 0

Factor out x + 284

(x - 250)(x + 284)= 0

Split

x - 250 = 0 \ or\ x + 284= 0

Solve for x

x = 250 \ or\ x =- 284

x can't be negative;

So:

x = 250

6 0
3 years ago
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