Answer:
I do not believe you can solve this unless the variable mean something and it is specified
Answer:
m =48
Step-by-step explanation:
1st step is to multiply both sides by 8
2nd step it would be 48=m
3rd step swap the sides.. m=48
Answer:
36cm
Step-by-step explanation:
Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.
![\mu = 250*0.08 = 20, \sigma = \sqrt{250}*0.01 = 0.158](https://tex.z-dn.net/?f=%5Cmu%20%3D%20250%2A0.08%20%3D%2020%2C%20%5Csigma%20%3D%20%5Csqrt%7B250%7D%2A0.01%20%3D%200.158)
What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{20.2 - 20}{0.158}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B20.2%20-%2020%7D%7B0.158%7D)
![Z = 1.27](https://tex.z-dn.net/?f=Z%20%3D%201.27)
has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
263.27 m^2
rectangle : 15 x 10 = 150 m^2
the half circle at the top has a diameter of 6m. therefore, it’s radius is 3m. if it is cut in half, the part removed from the triangle height is 3m. therefore, the height of the triangle is 35 -15 = 20; 20 - 3 = 17. the height of the triangle is 17. the triangle area formula is a = 1/2(bh).
a = 1/2 (10)(17)
a = 1/2 (170)
a = 85 m^2
the circle would be a = πr^2 but divided by 2 bc it’s a half circle
a = π(3)^2
a = π9
a = 28.27 m^2
150 + 85 + 28.27 = 263.27 m^2