Amount of water in the pool at the end of the day is 5457798.7 gallons
<u>Explanation:</u>
Given:
Initial amount of water in the pool = 45,000 gallons
Increase in amount = 0.75 in per minute
Time, t = 1 day
t = 24 X 60 min
t = 1440 min
So,
Increase in amount of water in 1 day = 0.75 in X 1440
= 1080 in
Volume of 1080 in of water = (1080 in)³
Volume from cubic inch to gallon = 5453298.7 gallon
Amount of water in the pool at the end of the day = 45000 + 5453298.7 gallon
= 5457798.7 gallon
Answer:
75 students out of 120
Step-by-step explanation:
75/120
So for this you will be using an exponential equation, which is 
with a=initial value, b=growth/decay, y = total balance, and x = # of years
In this case, a = 500, and since with this problem the initial value is growing, you will add 100% to 6% to get 106%, or 1.06. The equation will be formed as such: 
With this problem, just plug in 15 into x and solve for y: 
In short, after 15 years Tom will have $1198.28 in his account.
Answer:
1. -10x^2-x+6-10x 2-x+6 = -10x^2 - 22x + 12
2. 10x^2-510x 2-5 = 10x^2 - 1020x - 5
Step-by-step explanation:
hope this helps
if i did something wrong let me know so i can fix my answer
#Virgo2007
Answer:
a) x = 70
Step-by-step explanation:
70 (2) +20 +20
140 + 40
180
