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Ivahew [28]
3 years ago
5

Anyone know how to do this?

Mathematics
1 answer:
Finger [1]3 years ago
3 0

Answer:

X = 2

Step-by-step explanation:

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Algebra- systems of equations (x,y)<br> 3x + 4y = 56<br> x = 3y + 12
ElenaW [278]

Answer:

2

Step-by-step explanation:

simplify......dndjddjejdjdjehdeww

7 0
3 years ago
HELP PLZ I GIVE YOU BRAINLIEST IF YOU GET CORRECT PLZ I BEG YOU
DiKsa [7]

Answer:

Original number = 38

Step-by-step explanation:

10*x + y

x   = y - 5

10y + x = 2 (10x + y) +  7

10y + y - 5 = 2(10(y - 5) + y) + 7

11y - 5 = 2(10y - 50 + y ) + 7

11y - 5 = 2(11y - 50) + 7

11y - 5 = 22y - 100 + 7

11y - 5 = 22y - 93

11y + 88 = 22y

88 = 11y

y = 8

x = y - 5

x = 8 - 5

x = 3

So the original number is 38. Does that work?

3 is 5 less than 8.

83 = 2*38 + 7

83 = 76 + 7

83 = 83.         Yes it works.

8 0
3 years ago
(A) Write an expression that represents Sarah’s total pay last week. Represent her hourly wage with (w)?
garri49 [273]

Answer:

Step-by-step explanation:

7 0
3 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
The simplified form of 5√2 - 4√2/ √2 is... its estimated value is..
ankoles [38]

Answer:

2 answers available depending on paranthesis

Step-by-step explanation:

5√2-4√2/√2 = 5√2 - 4

if there is a parenthesis like

(5√2 - 4√2)/√2 = 1√2/√2 =1

7 0
2 years ago
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