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amid [387]
3 years ago
13

Nelson needs 3 and 3/4 cups of flour to make a loaf of bread and 2 and 2/3 cups of flour to make pretzels. How many cups of flou

r does Nelson need in all?
Mathematics
2 answers:
Helen [10]3 years ago
8 0

Answer:

6 5/12 cups.

Step-by-step explanation:

3 3/4 + 2 2/3

= 3 + 2 + 3/4 + 2/3

= 5 + 3/4 + 2/3

The LCM of 4 and 3 is 12 so we have:

5 + 9/12 + 8/12

= 5 + 17/12

= 5 + 1 5/12

= 6 5/12.

matrenka [14]3 years ago
4 0

Answer:

that is 6 and 5/ 12 cups of flour are required

Step-by-step explanation:

total number of cups required to make a loaf of bread

= 3 + ¾

making their denominators equal and that to 4

= 12/ 4 + 3/ 4

adding numerators

= (12 + 3)/ 4

= 15/ 4

total cups of flour required to make pretzels

= 2 + ⅔

making their denominators equal and that to 3

= 6/ 3 + 2/ 3

adding nunerators

= (6 + 2)/ 3

= 8/ 3

Total cups required:-

= 15/ 4 + 8/ 3

taking lcm of denominators to make the fractions equivalent

= {(15 × 3) + (8 × 4)}/ 12

= {45 + 32}/ 12

= 77/ 12

6 \frac{5}{ 12}

<em>that is 6 and 5/ 12 cups of flour are required</em>.

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Step-by-step explanation:

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Multiply the following rational expressions and simplify the result
GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

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                                   = \frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}

                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

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Answer:

not a function

Step-by-step explanation:

trust me i have been through this

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