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nadezda [96]
3 years ago
9

A salesman needed to sell a used car. He priced it at $4,500 the first day it was on the

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

$3960

Step-by-step explanation:

12% of $4,500 is 540.

Subtracting the 12% means taking away $540 from $4,500, which gives you $3960

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Graph 2x-5=2x+8 please
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Vondra wants to buy a charm bracelet. Oak Grove Fine Jewelry charges $16 per charm, plus $53 for the bracelet. Sandoval Jewelers
AveGali [126]

Answer:

The bracelet will cost 85$ and it'll have 2 charms.

Step-by-step explanation:

In order to find the total cost of the bracelet and how many charms it'd be we need to build an equation for each store. So we have:

Oak Grove:

total cost = 16*charm + 53

Sandoval:

total cost = 27*charm + 31

We then find the number of charm that'll make them equal, since the price has to be the same on both shops:

16*charm + 53 = 27*charm + 31

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The cost of the bracellet is:

total cost = 27*2 + 31 = 85 $

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How can you determine if you need to use a combination or permutation to count the number of outcomes? Which will usually have m
Nadya [2.5K]

Answer with Step-by-step explanation:

Permutation : It is an arrangement of r elements out of n elements.

Combination : it is a selection of r element out of n elements .

Suppose we have a set

S={1,2,3}

If two elements are taken at a time then

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Total number of outcomes=\frac{3!}{(3-2)!}

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Using combination formula

\binom{n}{r}=\frac{n!}{r!(n-r)!}

Total number of outcomes=\binom{3}{2}=\frac{3!}{2!1!}

Total number of outcomes=\frac{3\times2!}{2!}

Hence, total number of outcomes=3

Total number of outcomes determined by permutation have more outcomes.

Because permutation is an arrangement of elements  therefore, it consider order of arrangement of element   but combination is a selection of elements it does no consider order of elements

Arrangements of two elements out of 3 elements

{1,2},{2,3},{2,1},{3,2},{1,3},{3,1}

By using combination if two elements taken at a time then combination

{1,2},{2,3},{1,3}

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