A, I think
Lmk if im wrong
Umm... no...... I'm in Middle School but sorry though.
Given that the height of the ball has been modeled by h=120t-16t^2, the reasonable range will be found as follows:
maximum height is attained when h'(t)=0
given h=120t-16t^2
h'(t)=120-32t=0
thus solving for t, we get:
t=3.75 sec
thus the maximum time attained will be:
120(3.75)-16(3.75)^2=225 ft
Therefore the reasonable range will be [0≤h(t)≤225]
Square = identical sides.
therefore, 200ft^2 = (square root 200)^2
square root 200 = 14.14213562ft