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elena-s [515]
3 years ago
9

Can someone please help me with this? ​

Mathematics
1 answer:
geniusboy [140]3 years ago
8 0

Answer: B and D

Step-by-step explanation:

First, solve the terms inside of the parenthesis. As a general rule, whenever you multiply two terms that have the same base, you can add their exponents.

Applying this rule, the base in the problem is 6, and the exponents are 3 and -4. The sum of 3 and -4 leaves -1. Therefore, this is one of our solutions:

(6^-^1)^-^3

When you have an exponential term raised to another exponent, you can simply multiply the exponents. In the previous solution given above, multiply -1 and -3 to get 3. Therefore our second solution is:

6^3

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Slope= -1/3 passing through (9,-2)<br>point slop form?<br>slope intercept form?
erica [24]
Point slope:
y-(-2)=-1/3(x-9)
slope intercept:
solve the point slope form
y+2 = -1/3x+3
y=-1/3x+1
6 0
3 years ago
Write an equation of a line that is parallel to y=2x-5 that passes through the point (2,6).
inessss [21]

Answer: Parallel lines have the same slope

y = 2x +b

Use the given point (2, 5)

5 = 2(2) +b

b = 5 -4 = 1

The equation of the line is

y = 2x +1

Note general form of the slope-intercept form of a line is y = mx +b, where m is the slope and b is the y-axis intercept

Step-by-step explanation:

3 0
2 years ago
A cardboard box without a lid is to have a volume of 8,788 cm3. Find the dimensions that minimize the amount of cardboard used.
Montano1993 [528]

Answer:

  x = y = 26 cm; z = 13 cm

Step-by-step explanation:

The generic solution for the minimum material in an open-top box is that the box is square and half as high as it is wide. It is half a cube of twice the volume.

The dimensions of the square base are ...

  ∛(2·8788 cm³) = 26 cm

Then the height is half that, or 13 cm.

  x = y = 26 cm; z = 13 cm

_____

If you need to see the development, you can use the method of Lagrange multipliers to find the minimum area for the given volume;

  area = xy +2(xz +yz)

  volume = xyz = 8788

We require each of the partial derivatives of L with respect to x, y, z, and λ to be zero.

  L = xy +2(xz +yz) +λ(xyz -8788)

  partial with respect to x: 0 = y+2z +λyz

  partial with respect to y: 0 = x +2z +λxz

  partial with respect to z: 0 = 2x+2y +λxy

  partial with respect to λ: 0 = xyz -8788

From the first two equations, we have ...

  λ = (y +2z)/(yz) = 1/z +2/y

  λ = (x +2z)/(xz) = 1/z +2/x

Equating these expressions for λ, we find ...

  1/z +2/y = 1/z +2/x   ⇒   x = y

The third equation then tells us ...

  λ = (2x +2y)/(xy) = 2/y +2/x

Comparing this to either of the first two expressions for λ, we see ...

  1/z +2y = 2/x +2/y   ⇒   z = x/2

This is the result we started the answer with:

  x = y = 2z = ∛(2·8788 cm³)

7 0
3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

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We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

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2x=-3-4-\sqrt{5} or 2x=-3-4+ \sqrt{5}

2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

5 0
3 years ago
What does n equal in 2n+33
lana66690 [7]
N= -16.5

Subtract 33 then divide by 2
2n=-33
n=-33/2 or n=-16.5
4 0
3 years ago
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