Answer:
the last one 1/6
Step-by-step explanation:
1/2 x 1/3 = 1/6
-3+11p
first you add 1+2p that gets you -3 then you do 9p-4 and you get 11p from there you can either solve it, or leave it as is, depending on what your teacher wants.
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
C
Step-by-step explanation:
