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3 years ago

13

How many 7/8 yard long scarves can I make from 156 feet of fabric

1 answer:

maria [59]3 years ago

5 0

Now, there are 3 feet in 1 yard, so in 156 feet there are 156/3 or 52 yards.

how many times does 7/8 go into 52? let's check.

$\bf \cfrac{52}{\frac{7}{8}}\implies \cfrac{\frac{52}{1}}{\frac{7}{8}}\implies \cfrac{52}{1}\cdot \cfrac{8}{7}\implies \cfrac{52\cdot 8}{1\cdot 7}\implies \cfrac{416}{7}
\\\\\\
\textit{7 goes into 416 \underline{59 times}, with a \underline{remainder of 3}}\implies 59\frac{3}{7}$

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where p0 is the atmospheric pressure at sea level and k is a constant. If the atmospheric pressure is 14.7 lb/in.2 at sea level

balu736 [363]

Answer:

The value of pressure at an altitude of 10000 ft = 10 $\frac{lb}{in^{2} }$

Step-by-step explanation:

Given data

Atmospheric pressure $P_{0}$ = 14.7 $\frac{lb}{in^{2} }$

Pressure at 4000 ft = 12.6 $\frac{lb}{in^{2} }$

If temperature is constant then the atmospheric pressure is varies with the altitude according to law

P (h) = $P_{0}$ $e^{- kh}$ ------ (1)

where k= constant & h = height

12.6 = 14.7 $e^{- 4000k}$

0.857 = $e^{- 4000k}$

㏑ 0.857 = - 4000 k

-0.154 = - 4000 k

k = 3.85 × $10^{-5}$

Thus the atmospheric pressure at an altitude of 10,000 ft is

$P_{10000} =$ 14.7 × $e^{- kh}$ ----- (2)

Product of k & h is

k h = 3.85 × $10^{-5}$ × 10000

k h = 0.385

Put his value of k h = 0.385 in equation (2) we get

$P_{10000} =$ 14.7 × $e^{-0.385 }$

$P_{10000} =$ 10 $\frac{lb}{in^{2} }$

This is the value of pressure at an altitude of 10000 ft.

7 0

2 years ago

Please help with the image below

prisoha [69]

Answer:

150

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

In a normal distribution, the mean is ____ it's mean and mode

Blizzard [7]

In a normal distribution, the median (I think you meant to say) is equal to the mean and mode.

6 0

2 years ago

Please help me with this

zvonat [6]

Answer:

Hey there!

The answer is 6/7h=4.

This means that 6/7 of his brother's height is four feet, which is Bryce's height.

Let me know if this helps :)

4 0

2 years ago

The lengths of pregnancies are normally distributed with a mean of 269269 days and a standard deviation of 1515 days. a. Find th

kati45 [8]

Answer:

a. 0.38%

b. 266.75 days

Step-by-step explanation:

We have the following data, mean (m) 269 and standard deviation (sd) 15, therefore:

a. The first thing is to calculate the number z:

z (x) = (x - m) / sd

z (309) = (309-269) / 15 = 2.67

When looking in the normal distribution table (attached), we have that at this value of z, the probability is:

P (z> 2.67), that is to say we must look in the table -2.67 and this value corresponds to 0.0038, that is to say 0.38%

b. Find the z-value with a left tail of 44%, i.e. 0.44. We look in the table for this value and what value of z corresponds.

invNorm (0.44) = -0.15

Find the corresponding number of days:

x = z * sd + m

we replace

d = -0.15 * 15 + 269 = 266.75 days

7 0

2 years ago