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UkoKoshka [18]
3 years ago
14

(x+2)-(X-2) PLEASE HELP ME

Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

4 is the answer

Step-by-step explanation:

x+2-x+2= 4

lilavasa [31]3 years ago
6 0

Answer:

If you are talking about subtracting it is 4

Step-by-step explanation:

(x+2)-(X-2)=4

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Mia buys 5 yards of ribbon to make bracelets.She needs 18 inches of ribbon to make 1 bracelet.How many bracelets can Mia make if
snow_tiger [21]
To find the number of bracelets Mia can make, she will convert 5 yards to inches and then break that into groups of 18 inches.

5 x 36 = 180 inches

180/18= 10

Mia can make 10 bracelets.
8 0
3 years ago
PLEASE HELP I WILL MARK!!
Rina8888 [55]

answer is D

Explamation:

given points are (7,9) and (12,11)

mid \: point \: of \: x =  \frac{x1 + x2}{2 }  =  \frac{7 + 12}{2}  = 9.5 \\ midpoint \: of \: y =  \frac{y1 + y2}{2}  =  \frac{9 + 11}{ 2} = 10

therefore the mid point is (9.5,10)

8 0
3 years ago
8
svetoff [14.1K]

Answer:

5+9+10+10+5+2+5+2

Step-by-step explanation:

48÷8=6

6 is median of given data

5 0
2 years ago
Read 2 more answers
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allsm [11]

Answer:

wow.

Step-by-step explanation:

8 0
2 years ago
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
  • A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
5 0
3 years ago
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