Y+4=-2(x+1)
This is the point slope form (y-y1) =m(x-x1)
I hope it will helped!
Answer:
x = - 4 y = - 4
Step-by-step explanation:
x+y= - 8
-9x-6y=60
First, solve for x in the first equation:
x+y = - 8 Subtract y from both sides
x + y - y = -8 - y y cancels on the left
x = - 8 - y
Now plug in what you found for x into the 2nd equation and solve for y.
- 9x - 6y = 60
-9(- 8 - y) - 6y = 60 Multiply out
72 + 9y - 6y = 60
72 + 3y = 60 Subtract 72 from both sides
72 - 72 + 3y = 60 - 72 72 cancels on the left
3y = - 12 Divie both sides by 3
3y/3 = -12/3 3 cancels on the left because 3/3 = 1
y = -4
Now plug your answer for y back into the first equation to get x.
x + y = -8
x + (-4) = - 8 Add 4 to each side
x - 4 + 4 = - 8 + 4 4 cancels on the left
x = -4
x = - 4 and y = - 4
The answer is 4 pensioners
Answer:
amdlkmflakmflkmasdklmflkansdlkfwelkma;lkdsmlfdsnalkme;klamdlfsndldkanfdlknadlkfn;alkndflkandslknaslfknalkdfnladkfsnlkandslfkn
Step-by-step explanation:
Answer:
ax²+bx+c
ax²+bxy+cy²
Step-by-step explanation:
A quadratic expression is one where the maximum degree of the variable or variables ( in case of more than one variable the sum of the degree of the variables in a single term considered) is 2.
For example:
A quadratic expression of a single variable is ax²+bx+c {Where a, b, and c are the arbitrary constants}
A quadratic expression with two variables is ax²+bxy+cy² {Where a, b, and c are the arbitrary constants}
And, a quadratic expression with three variables is ax² +by² +cz² +dxy +eyz +fzx {Where a, b, c, d, e, f are the arbitrary constants} (Answer)
