The answer is 16
And also , can people please stop posting did you get the answer yet, just so you could get the points. They only take two answers, and that's a waste of somebody who could've answered or helped.
37 is the median of the set of data
Hope this helps :)
Answer:
The data is skewed, and the lowest number of crackers in a package was 7
Step-by-step explanation:
Hi,
First of all, since the question was incomplete due to the missing capture of the range shown on the box plot. I attached it for you so I could answer your question as well.
Taking into consideration the attached image's information, symmetric would be right down the middle, but it is not.
The image shows that it is <em>positively skewed with the lowest number being 7.</em>
Answer:
<u>The correct answer is 58 cars.</u>
Step-by-step explanation:
Cars in the junkyard before the truck arrived with some = 178
Cars after the truck brought into the junkyard some more= 236
Cars brought in by the truck = 236 - 178
Cars brought into the junkyard by the truck = 58
<u>The number of cars brought by the truck is 58 cars.</u>
Looks like we're given

which in three dimensions could be expressed as

and this has curl

which confirms the two-dimensional curl is 0.
It also looks like the region
is the disk
. Green's theorem says the integral of
along the boundary of
is equal to the integral of the two-dimensional curl of
over the interior of
:

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of
by


with
. Then

