This is a 3-4-5 triangle.
Remember,
SOH-CAH-TOA
S(ine) = O(pposite)/H(ypotenuse)
C(osine) = A(djacent)/H(ypotenuse)
T(angent) = O(pposite)/A(djacent)
In Cosine, the adjacent = 3, and the Hypotenuse = 5
Hypotenuse is the longest side.
3,4,5 is the triangle that fits inside, therefore, the Opposite is 4, and Adjacent is 3
T(angent) = O(pposite)/A(djacent)
Plug in the numbers
T = 4/3
tan = 4/3 is your answer
hope this helps
I’m not too sure if I did it correct, but the answer I got was -6x^2+36. I just assumed you’d solve it as usual and then multiply (-3) after distributing-2 to x^2-6. Hope this helps.
Answer:
B
7 less than 3 times a number (X) is (3x-7), and then the sum of these two numbers means we have (3x-7)+X, and then we know this equals 109, leaving us with:
(3x-7)+x = 109
Answer:
There is enough evidence to make the conclusion that the population mean amount of time to assemble the Meat Man barbecue is not equal to 10 minutes (P-value=0.009).
Step-by-step explanation:
We have to perform an hypothesis test on the mean.
The null and alternative hypothesis are:

The significance level is
.
The test statistic t can be calculated as:

The degrees of freedom are:

The P-value (two-tailed test) for t=2.737 and df=49 is P=0.00862.
This P-value (0.009) is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.
There is enough evidence to make the conclusion that the population mean amount of time to assemble the Meat Man barbecue is not equal to 10 minutes.