Here is my work for the problem. Hope this helps!
<span>"5th root of x^4" hoil
</span>
Answer:
1/3 (one third)
Because there are only 4 numbers on 2 die that have numbers less than 3 so 4 twelfths equals one third
Step-by-step explanation:
Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
