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3 years ago

First one that gets it correctly gets branlyest

Mathematics

1 answer:

sasho [114]3 years ago

5 0

Answer:

200 in2

Step-by-step explanation:

diameter= 15 in. so raduis = 15/2

area of circle = πr2

= 22/7 * 15/2 *15/2

= 176.79

rounding to the nearest 100, its 200 in2

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Slope 0; through (-5, -1)<br> with steps please.

posledela

Step-by-step explanation:

0 slope means it has in x.

so the equation is y=-1, because that is the coord for the points'y axsis

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3 years ago

a 4inch wide by 6inch long picture is placed on a solid mat that forms a frame around it. the mat is 8 inches long. the mat and

gulaghasi [49]

The area of the mat is 42.67 inches^2 or 42 and 2/3 in^2

7 0

2 years ago

Dharmesh has a square garden with the perimeter of 132 feet is the area of the garden greater than 1000 square feet

k0ka [10]

Yes, the area of the garden is greater than 1000 sq. ft.

132 = total perimeter
A square has 4 sides
132/4 = 33
A= LxW
A= 33 x 33
A= 1089 sq. ft.

7 0

3 years ago

An auto mechanic converts a metric part to 0.492 in. The part comes only in fractional sizes given to the nearest 64th of an inc

tatuchka [14]

Answer:

the closest part the mechanic can chose is 0.5 inch

Step-by-step explanation:

fractional sizes given to the nearest 64th of an inch = 1/64 = 0.0156

the closest size to 0.492in = 0.492 + 0.0156 = 0.5076 inches

approximately, the closest part the mechanic can chose is 0.5 inch

4 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

makkiz [27]

Answer:

Step-by-step explanation:

$x + 2y + 3z = 12$

$z=\frac{12-x-2y}{3}$

Volume = $V=f(x,y) = xy(\frac{12-x-2y}{3} )$

find partial derivatives using product rule

$f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)$

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

6 0

2 years ago