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3 years ago

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361_PROP1.3_MAT_IP_Grocery_Store_and_Righteous_Rates_2021.doc GROCERY STORE RATES 3611342 Javier went to the store with his aunt

to get some food for a picnic. 1) Find the cost of ONE unit of each item 2) Find the total cost of the purchases Javier and his aunt made. Wed. Nov. 18th Takis 5 bags for $6 Takis Tals Takie Tak Takis Price per bag of Takis:

1 answer:

yuradex [85]3 years ago

7 0

Omg lol it has takis in it ksjdjsndjc

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Mr. Nicolas is putting up strings of blue and white lights for the holidays. The ratio of blue to white lights is 5 to 6. If he

SVEN [57.7K]

Hello there.

Question: <span>Mr. Nicolas is putting up strings of blue and white lights for the holidays. The ratio of blue to white lights is 5 to 6. If he has 77 strings, how many strings are white lights?

Answer: 5:6
Add the numbers:
5 + 6 = 11
Divide this number by the total:
77/11 = 7
Multiply values by this number:
5 x 7 = 35
6 x 7 = 42
To check:
35 + 42 = 77.
Therefore your answer is 42.

</span>Hope This Helps You!
Good Luck Studying ^-^

8 0

3 years ago

You wish to borrow $8000 for debt consolidation. The bank's interest rate for a personal loan is 7.2%. What is your monthly paym

Lisa [10]

<h3>The monthly payment is $242.44 for loan to paid off in 3 years.</h3>

Step-by-step explanation:

The amount borrowed = Principal = $8000

The rate of interest = 7.2%

Time (T) = 3 years

Now, Simple Interest = $\frac{P\times R \times T}{100}$

$\implies SI = \frac{8000 \times 7.2 \times 3}{100} = 1,728$

So, the total interest = $1728

Now, <u>Amount to be paid = Principal + Interest</u>

⇒ A = $8000 + $1728 = $8728

Also, 1 year = 12 months

⇒ 3 years = 3 x 12 months = 36 months

So, total amount to be paid in 36 months is $8728.

⇒The amount to be paid in 1 month is $(\frac{8728}{36} ) = 242.44$

Hence, the monthly payment is $242.44 if loan is to paid off in 3 years.

3 0

3 years ago

I need help please help me

harkovskaia [24]

We substitute in c using 9, it will be as follows:
5 ×[(-6×9)+4] = 5 × (-54+4) = 5 × (-50) = -250

3 0

3 years ago

(5 points) An urn contains two blue balls denoted by B1 and B2, and three white balls denoted by W1, W2 and W3. One ball is draw

never [62]

Answer:

The probability of the event that first ball that is drawn is blue is $\frac 25$ .

Step-by-step explanation:

Probability:

If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is

$P(E)=\frac{\textrm{The number of outcomes E}}{\textrm{The total number outcomes of S}}$

Given that,

An urn contains two balls B₁ and B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.

Total number of ball =(2+3) =5

The number ways of selection 2 ball out of 5 ball is

=5²

=25

Total outcomes = 25

List of all outcomes in the event that the first ball that is drawn is blue are

B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ , B₂W₁ , B₂W₂ , B₂W₃

The number of event that the first ball that is drawn is blue is

=10.

The probability of the event that first ball that is drawn is blue is

$=\frac{10}{25}$

$=\frac25$

3 0

4 years ago

Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me

Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean $\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$\mu = 11.5, \sigma = 4$

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have $n = 50, s = \frac{4}{\sqrt{50}} = 0.5657$

This probability is 1 subtracted by the pvalue of Z when X = 12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{12 - 11.5}{0.5657}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so $mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28$

This probability is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 575}{28.28}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c. What is the approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers.

This is X when Z has a pvalue of 0.95. So it is X when Z = 1.645.

$Z = \frac{X - \mu}{s}$

$1.645 = \frac{X- 575}{28.28}$

$X - 575 = 28.28*1.645$

$X = 621.5$

The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

5 0

3 years ago