So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a 
chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is 
, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:
Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is
, and the probability of picking the second red ball is 
and the probability of picking the green ball is
. We want to multiply thm again, as per the multiplication rule like the last problem.
Answer:
x>1.16
Step-by-step explanation:
Subtract 5 from each side to get 4x>14-8x
change the symbol from +8 to -8
4x> 14+ (-8x)
than add 8x to both sides
12x > 14
which would mean that x has to be greater than 1.16
x>1.16
Answer: the radius of the basketball when the volume is v
Step-by-step explanation:
Answer:
Solution
p = {-3, 1}
Step-by-step explanation:
Simplifying
p2 + 2p + -3 = 0
Reorder the terms:
-3 + 2p + p2 = 0
Solving
-3 + 2p + p2 = 0
Solving for variable 'p'.
Factor a trinomial.
(-3 + -1p)(1 + -1p) = 0
Subproblem 1
Set the factor '(-3 + -1p)' equal to zero and attempt to solve:
Simplifying
-3 + -1p = 0
Solving
-3 + -1p = 0
Move all terms containing p to the left, all other terms to the right.
Add '3' to each side of the equation.
-3 + 3 + -1p = 0 + 3
Combine like terms: -3 + 3 = 0
0 + -1p = 0 + 3
-1p = 0 + 3
Combine like terms: 0 + 3 = 3
-1p = 3
Divide each side by '-1'.
p = -3
Simplifying
p = -3
Subproblem 2
Set the factor '(1 + -1p)' equal to zero and attempt to solve:
Simplifying
1 + -1p = 0
Solving
1 + -1p = 0
Move all terms containing p to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1p = 0 + -1
Combine like terms: 1 + -1 = 0
0 + -1p = 0 + -1
-1p = 0 + -1
Combine like terms: 0 + -1 = -1
-1p = -1
Divide each side by '-1'.
p = 1
Simplifying
p = 1
Solution
p = {-3, 1}
Answer:
- hits the ground at x = -0.732, and x = 2.732
- only the positive solution is reasonable
Step-by-step explanation:
The acorn will hit the ground where the value of x is such that y=0. We can find these values of x by solving the quadratic using any of several means.
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<h3>graphing</h3>
The attachment shows a graphing calculator solution to the equation
-3x^2 + 6x + 6 = 0
The values of x are -0.732 and 2.732. The negative value is the point where the acorn would have originated from if its parabolic path were extrapolated backward in time. Only the positive horizontal distance is a reasonable solution.
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<h3>completing the square</h3>
We can also solve the equation algebraically. One of the simplest methods is "completing the square."
-3x^2 +6x +6 = 0
x^2 -2x = 2 . . . . . . . . divide by -3 and add 2
x^2 -2x +1 = 2 +1 . . . . add 1 to complete the square
(x -1)^2 = 3 . . . . . . . . written as a square
x -1 = ±√3 . . . . . . . take the square root
x = 1 ±√3 . . . . . . . add 1; where the acorn hits the ground
The numerical values of these solutions are approximately ...
x ≈ {-0.732, 2.732}
The solutions to the equation say the acorn hits the ground at a distance of -0.732 behind Jacob, and at a distance of 2.732 in front of Jacob. The "behind" distance represents and extrapolation of the acorn's path backward in time before Jacob threw it. Only the positive solution is reasonable.
