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3 years ago

I need help on both of these questions can you guys help me?

Mathematics

2 answers:

xenn [34]3 years ago

6 0

What she said what she said

sp2606 [1]3 years ago

5 0

The area of the sector is 42.4 feet and the area for the second is 50 :)

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Which of the tables represents a function? Help please i’ll mark brainliest

Helga [31]

Answer:

Table B

Step-by-step explanation:

If you see any number in the input being used more than once, it is not a function. If all numbers of the input are different, it is a function.

Only Table B is a function since all input numbers are different.

5 0

3 years ago

I need help plz with this

madam [21]

Answer:

a) 390

b)108

I hope this answer was helpfull for you

5 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

The diagram represents an enlargement of a rectangle by a scale factor of 4.

Tpy6a [65]

Answer:

D. 16 inches by 8 inches

Step-by-step explanation:

We have been given an image of two rectangles and we are asked to find the dimensions of the enlarged rectangle.

Since we have been given that the original rectangle is enlarged b a scale factor of 4, so to find the dimensions of enlarged rectangle we will multiply the dimensions of original rectangle by 4.

$\text{Length of enlarged rectangle}=4\times 4\text{ inch}$