The second male cone in cycas plant is formed by the activity of
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So I don’t see answer choices here, but your answer is 50% of the offspring will be homozygous dominant with RR, and 100% of them will carry a homozygous dominant gene of Rr
If you take the two sets and put them into a punnett square, it would look like this (image attached):
When the two sets of alleles are crossed, you would end up with half of your pairs being fully dominant (RR), and the other half being dominant while containing a recessive gene (Rr). Since there’s only one recessive gene in these pairs, it gets overridden and the pair itself is dominant.
So your answer is 50% will be homozygous dominant with RR!
If you take the two sets and put them into a punnett square, it would look like this (image attached):
When the two sets of alleles are crossed, you would end up with half of your pairs being fully dominant (RR), and the other half being dominant while containing a recessive gene (Rr). Since there’s only one recessive gene in these pairs, it gets overridden and the pair itself is dominant.
So your answer is 50% will be homozygous dominant with RR!