Answer:
52
Step-by-step explanation:
13 times 4
I think 5 and 2 are linear pairs, 3 and 4 are complementary angles, 1 and 2 are vertical angles, and 5 and 2 are also supplementary angles
I could be wrong but I’m pretty sure!!
Smallest angle is
°
<u>Step-by-step explanation:</u>
Here we have , Quadrilateral WXYZ has interior angles that meet the following criteria:
Angles W and X are congruent.
According to question , angles are congruent i.e. Both angle measure same
⇒ ![X=W](https://tex.z-dn.net/?f=X%3DW)
Now ,
• The smallest angle's measure is 100° less than twice the measure of W.
According to above statement we have ,
Smallest angle = ![2W-100](https://tex.z-dn.net/?f=2W-100)
• The largest angle's measure is 10º more than twice the measure of X. ( correction , in question given as 2X )
According to above statement we have ,
Largest angle = ![10+2X=10+2X](https://tex.z-dn.net/?f=10%2B2X%3D10%2B2X)
Now , We know that sum of all 4 angles in 360 i.e.
⇒
{ X=W }
⇒ ![6W-90=360](https://tex.z-dn.net/?f=6W-90%3D360)
⇒ ![6W=450](https://tex.z-dn.net/?f=6W%3D450)
⇒ ![W=75](https://tex.z-dn.net/?f=W%3D75)
Smallest angle is :
Therefore , Smallest angle is
° .
Area = (angle/2π)*π*r^2 because the area of a sector is basically the total area (π*r^2) divided by the fraction of the whole (angle/2π). 2π = the whole of the circle in radians.
So for your problem Area = (5π/2/2π)*π*(4^2) = (5π/4π)*π*(16) = (5/4)*(3.14)*(16) = 20*(3.14) = 62.8
Hope this helps!
157ft2 because area of sector AOB equals 180/360 × πr2