Answer:
60.26yd³
Step-by-step explanation:
Since we are not given the diagram, let us assume that;
Length of the base = 5.4yd
Height of the pyramid = 6.2yd
volume of the square pyramid = BH/3
B is the base area = L^2
B = 5.4²
B = 29.16yd²
H = 6.2yd
Get the volume
volume of the square pyramid = 29.16*6.2/3
volume of the square pyramid = 180.792/3
volume of the square pyramid = 60.26yd³
Hence the volume of the square pyramid to nearest hundredth is 60.26yd³
Answer:
α = 62°
β = 56°
gamma = 90°
Step-by-step explanation:
ΔAOB is isosceles, so m∠A = m∠ABO = 28
28 + 28 + m∠AOB = 180
m∠AOB = 180 - 28 - 28 = 124
β = 180 - 124 = 56
arcAB = 124
ΔBOC is isosceles. α = m∠BCO = 1/2(arc AB) = 1/2(124) = 62
∠D is inscribed in a semicircle
m∠D = gamma = 90°
Answer:
The number is -2
Step-by-step explanation:
step 1
Find the reciprocal of 2/3
Remember that when multiply a number by its reciprocal, the result is 1
so
The reciprocal of 2/3 is 3/2
step 2
Let
x-----> the number added to the numerator and denominator
Solve for x
step 3
verify
substitute x=-2
Simplify
----> is ok
therefore
The number is -2
Answer: 3x=3
Step-by-step explanation: Let's divide this into parts--
1. Adding the x variables: -2x+5x or 5x-2x = 3x.
2. Adding the y variables: y-y or -y+y = 0. (The negative and the positive y cancel each other out.)
3. Adding the numbers: 8-5 or -5+8 = 3.
Now just put it back into an equation: 3x + 0 = 3.
We don't need to add the 0, so the equation changes into 3x = 3.
