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OverLord2011 [107]
2 years ago
15

An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo

re over flying a road junction. Calculate A. Distance of airplane from ikeja airport when it was directly above the road junction B. The bearing of the airplane from ikeja airport at this instant
Mathematics
1 answer:
Nata [24]2 years ago
6 0

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

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Answer:

15) Ellen is 12 years old.

16) Don't know what value you are looking for but x=(17/4) while y=(7/4) since the set of equations is 2x-2y=5 and x+y=6.

Step-by-step explanation:

15) Ellen (E) is currently twice as old as Maria (M).

Twice means to multiply by 2.

E=2M is therefore the equation for this part of the problem.

In 6 years, Maria (M) will be 2/3 as old as Ellen (E).  Keep in my Maria as aged 6 years (M+6) and Ellen as aged 6 years (E+6):

M+6=(2/3)(E+6).

So we have this system to solve:

E=2M

M+6=(2/3)(E+6).

I'm going to replace the E in the second equation with 2M since the first equation says E=2M:

M+6=(2/3)(E+6) with E=2M:

M+6=(2/3)(2M+6)

Distribute:

M+6=(4/3)M+(12/3)

Reducing 12/3 to 4:

M+6=(4/3)M+4

Subtract 4 on both sides:

M+2=(4/3)M

Subtract M on both sides:

2=(4/3)M-M

Find a common denominator:  

2=(4/3)M-(3/3)M

Combine like terms:

2=(1/3)M

Multiply both sides by the reciprocal of 1/3 which is 3:

3(2)=3(1/3)M

6=1M

6=M

M=6

Maria is six years old.

Recall E=2M.

So if M=6, then E=2(6)=12.

So currently E is twice as old as M since 6(2)=12.

In six years, M will be 12 which E will be 18.

M (12) is two-thirds as old as E (18) since 12=2/3(18)

16)

2x-2y=5

 x + y=6

Your question doesn't state which value it is looking for.

Anyways I'm going to solve the system for the point (x,y) and then you can decide which part of this answer to use.

I'm going to solve this system by elimination.  Each equation already has the same form: ax+by=c. I just need a column with the variables to be opposite or the same.

I'm going to multiply both sides of equation 2 by 2:

2x-2y=5

2x+2y=12

Now I have opposites in a column: -2y and 2y.

When you add opposites you get 0 so this is what you want to use elimination.

We are going to add the equations now:

2x-2y=5

2x+2y=12

------------------Adding!

4x+0y=17

4x      =17

Divide both sides by 4:

 x      =17/4

Now if x=17/4 and x+y=6, then we have that (17/4)+y=6.

Subtracting 17/4 on both sides gives us y=6-(17/4).

Finding a common denominaotr gives us y=(24/4)-(17/4).

Simplifying this gives us y=(7/4).

The point of intersection (the solution) is (17/4 ,  7/4)

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Two angles are called complementary when their measures add to 90 degrees. ∠1 is 60 degrees ∠2 is 30 degrees so if you add it up, the answer is  90 degrees.

∠4 + ∠3 = answer has to be 90 degrees to call it a complementary angle

30 degrees + 60 degrees = 90 degrees

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